x=0.0038x^2-0.41x+36.95

Solution for x=0.0038x^2-0.41x+36.95 equation:

x=0.0038x^2-0.41x+36.95

We move all terms to the left:

x-(0.0038x^2-0.41x+36.95)=0

We get rid of parentheses

-0.0038x^2+x+0.41x-36.95=0

We add all the numbers together, and all the variables

-0.0038x^2+1.41x-36.95=0

a = -0.0038; b = 1.41; c = -36.95;
Δ = b2-4ac
Δ = 1.412-4·(-0.0038)·(-36.95)
Δ = 1.42646
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.41)-\sqrt{1.42646}}{2*-0.0038}=\frac{-1.41-\sqrt{1.42646}}{-0.0076}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.41)+\sqrt{1.42646}}{2*-0.0038}=\frac{-1.41+\sqrt{1.42646}}{-0.0076}
$